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$\mathbf{\pi N \longrightarrow \omega \pi N}$

Here we utilize once again the results of Golubeva et al. [GKC97] and assume a constant cross sections for all channels and define

\begin{displaymath} \sigma_{\pi N \rightarrow \omega \pi N}=\sigma^{Golubeva} . \end{displaymath}


Oliver Buss 2005-03-16