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$\mathbf{\pi N \longrightarrow \phi N }$

Utilizing the result of Golubeva et al. [GKC97] for $\pi^- p \rightarrow \phi n$ we define
$\displaystyle \sigma_{\pi^- p \rightarrow \phi n}$ $\textstyle =$ $\displaystyle \sigma^{\mathrm{Golubeva}}_{\pi^- p \rightarrow \phi n}$ (2.1)
$\displaystyle \sigma_{\pi^+ n \rightarrow \phi p}$ $\textstyle =$ $\displaystyle \frac{\left\langle 1 \frac{1}{2} ; 1 -\frac{1}{2} \vert \frac... ... \right\rangle^{2} } \sigma^{\mathrm{Golubeva}}_{\pi^- p \rightarrow \phi n}$ (2.2)
$\displaystyle \sigma_{\pi^0 p \rightarrow \phi p}$ $\textstyle =$ $\displaystyle \frac{\left\langle 1 \frac{1}{2} ; 0 \frac{1}{2} \vert \frac{... ... \right\rangle^{2} } \sigma^{\mathrm{Golubeva}}_{\pi^- p \rightarrow \phi n}$ (2.3)
$\displaystyle \sigma_{\pi^0 n \rightarrow \phi n}$ $\textstyle =$ $\displaystyle \frac{\left\langle 1 \frac{1}{2} ; 0 -\frac{1}{2} \vert \frac... ... \right\rangle^{2} } \sigma^{\mathrm{Golubeva}}_{\pi^- p \rightarrow \phi n}$ (2.4)


Oliver Buss 2005-03-16